2x^2-25x=-3x^2-4x-18

Solution for 2x^2-25x=-3x^2-4x-18 equation:

2x^2-25x=-3x^2-4x-18

We move all terms to the left:

2x^2-25x-(-3x^2-4x-18)=0

We get rid of parentheses

2x^2+3x^2+4x-25x+18=0

We add all the numbers together, and all the variables

5x^2-21x+18=0

a = 5; b = -21; c = +18;
Δ = b2-4ac
Δ = -212-4·5·18
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-9}{2*5}=\frac{12}{10}
=1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+9}{2*5}=\frac{30}{10}
=3
$